The graph of $ \(y = ax^2 + bx + c\) \( passes through the points \) \((0, 2)\) \(, \) \((1, 4)\) \(, and \) \((-1, 0)\) \(. Find the values of \) \(a\) \(, \) \(b\) \(, and \) \(c\) $.
We can factorize the quadratic equation as $ \((x + 6)(x - 1) = 0\) \(, which gives us \) \(x = -6\) \( or \) \(x = 1\) $. hkcee 2010 maths paper 2 solution
HKCEE 2010 Maths Paper 2 Solution: A Comprehensive Guide** The graph of $ \(y = ax^2 +